[ad_1]
![](https://1.bp.blogspot.com/-7EqJ443LRHI/YOHFOPJhapI/AAAAAAAATf4/u_oAocGhAx8CA9YJmWJG90Ifn5lXBNCzACLcBGAsYHQ/s320/m0652_v.png)
The size of a matchstick is 1 unit, so within the structure above 12 matchsticks have been used to create an space “W” of three sq. models. (see puzzle 121 and likewise how space W was calculated beneath)
There’s one other technique to create 3 sq. models, however you might NOT MOVE the matchsticks which from line AC. Can you discover it?
Pay attention to the calculations beneath as you may want a number of the info in your answer.
The realm W was calculated as:
= Complete space ABC – space X – space Y – space Z
= 1/2(3 X 4) – 1 – 1 – 1
= 3 sq. models
Angle 𝛳 was calculated as:
= arcsine(AB/AC)
= arcsine(3/5)
= 36.869898 levels
Present Reply
![](https://1.bp.blogspot.com/-CXg3J4qs_JU/YOHcTMQ8qYI/AAAAAAAATgA/iVZA7iSxFHEVESoYDHSyAot2fjHtRJx0wCLcBGAsYHQ/s320/m0652_a.png)
To calculate the peak:
sin𝛳 = peak/1
peak = sin(36.869898)
peak = 0.6 unit
The realm of the parallelogram is:
= base X peak
= 5 X 0.6
= 3 sq. models
Disguise Reply
[ad_2]
Source_link